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- Name: Oracle Cloud Infrastructure 2023 Foundations Associate
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NEW QUESTION: 1
A security analyst received a SIEM alert regarding high levels of memory consumption for a critical system. After several attempts to remediate the issue, the system went down. A root cause analysis revealed a bad actor forced the application to not reclaim memory. This caused the system to be depleted of resources.
Which of the following BEST describes this attack?
A. Array attack
B. Memory corruption
C. Injection attack
D. Denial of service
Answer: B
NEW QUESTION: 2
従業員は、Webブラウザを使用してインターネット上のhttps://example.comに接続します。 Webサーバーの証明書は、プライベート内部CAによって署名されました。このトラフィックを検査しているFortiGateは、完全なSSL検査用に構成されています。
この展示は、このインスタンスで呼び出されるポリシーに適用されるSSL / SSH検査プロファイルの構成設定を示しています。他のすべての設定はデフォルトに設定されています。 FortiGateにインポートされた証明書はありません。展示を見て、次の質問に答えてください。
どの証明書が従業員のWebブラウザに提示されますか？
A. Fortinet_CA_Untrustedによって署名された証明書。
B. Fortinet_CA_SSLによって署名された証明書。
C. Webサーバーの証明書。
D. プライベート内部CAによって署名されたユーザーの個人証明書。
Answer: B
NEW QUESTION: 3
Given:
import java.util.*;
public class AccessTest {
public static void main(String[] args) {
Thread t1 = new Thread(new WorkerThread());
Thread t2 = new Thread(new WorkerThread());
t1.start(); t2.start; // line1
}
}
class WorkPool {
static ArrayList<Integer> list = new ArrayList<>(); // line2
public static void addItem() { // line3
list.add(1); // Line4
}
}
class WorkerThread implements Runnable {
static Object bar = new Object ();
public void run() { //line5
for (int i=0; i<5000;i++) WorkPool.addItem(); // line6
}
}
Which of the four are valid modifications to synchronize access to the valid list between threads t1 and t2?
A. Replace line 4 with:
synchronized (list) (list.add(1);)
B. replace line 6 with:
Synchronized (this) {for (in i = 0, i<5000, i++) WorkPool.addItem(); }
C. Replace line 6 with:
synchronized (bar) {for (int i= 0; i<5000; i++) WorkPool.addItem(); }
D. Replace line 3 with:
synchronized public static void addItem () {
E. Replace Line 2 with:
static CopyWriteArrayList<Integer> list = new CopyWriteArrayList<>();
F. Replace line 1 with:
Synchronized (t2) (t1.start();) synchronized(t1) (t2.start();)
G. Replace line 5 with:
Synchronized public void run () {
Answer: B
Explanation:
Away to create synchronized code is with synchronized statements. Unlike synchronized methods, synchronized statements must specify the object that provides the intrinsic lock: For example:
public void addName(String name) {
synchronized(this) {
lastName = name;
nameCount++;
}
nameList.add(name);
}
In this example, the addName method needs to synchronize changes to lastName and
nameCount, but also needs to avoid synchronizing invocations of other objects' methods. Without
synchronized statements, there would have to be a separate, unsynchronized method for the sole
purpose of invoking nameList.add.
Reference: The Java Tutorial,Intrinsic Locks and Synchronization
NEW QUESTION: 4
Exhibit:
BGP is flapping after the Copp policy is applied. What are the two solutions to fix the issue?
(Choose two)
A. Configure BGP in the COPP-CRITICAL-7600 ACL
B. Configure IP CEF to CoPP policy and BGP to work
C. Configure a three-color policer instead of two-color policer under class COPP-CRITICAL-
7600
D. Configure a higher value for CIR under the default class to allow more packets during peak traffic
E. Configure a higher value for CIR under the class COPP-CRITICAL-7600
Answer: A,D
Explanation:
Explanation
The policy-map COPP-7600 only rate-limit HTTP & HTTPS traffic (based on the ACL conditions) so any BGP packets will be processed in the class "class-default", which drops exceeded BGP packets. Therefore we have two ways to solve this problem:
+ Add BGP to the ACL with the statement "permit tcp any any eq bgp"
+ Configure higher value for CIR in default class as 2Mbps is too low for web traffic (http &
https)
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